Show that 3 log 4 - 2 log 6 + log (18) 2/3- log (96root 2).
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3log(4)−2log(6)+log(18
2
3
)
log( {4}^{3} ) - log( {6}^{2} ) + log( {9}^{3} )log(4
3
)−log(6
2
)+log(9
3
)
log( \frac{ {4}^{3} {9}^{3} }{ {6}^{2} } )log(
6
2
4
3
9
3
)
log( \frac{ {36}^{3} }{36} )log(
36
36
3
)
log( {36}^{2} )log(36
2
)
2 log(36)2log(36)
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