Show that (3a- 7b)^2 + 84ab = (3a + 7b)^2
Answers
Answered by
1
Answer:
Firstly we solve LHS
(3a-7b)^2+84b
(3a)^2-2×3a×7b+(7b)^2+84b
9a^2-42ab+49b^2+84ab
9a^2+42ab+49b^2
Now we solve RHS
(3a)^2+2×3a×7b+(7b)^2
9a^2+42ab+49b^2
Hence proved LHS = RHS
Answered by
0
Step-by-step explanation:
(3a-7b)²+84ab
= (3a)² + (7b)² - 2x3ax7b + 84 ab
= 9a+49b- 42ab + 84ab
= 9a+49b +42ab
= (3a)² + (7b)² + 2x3ax7b
= (3 a+7b)² [∵a+b+2ab= (a+b)]
Hence, proved that
(3 a-7b)² +84ab= (3a+7b)²
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