Question

show that 4 n cannot end with digit 0 or 5 for any natural number N

Answer 1

For a digit to end with 0 it should have both 2 and 5 as a factor.

After factorizing 4 you get 4= 2*2
=2^2
Therefore 4^n= 2^2*n

It only has 2 as a factor and 5 is missing.
Hence any number of the form 4^n (where n is any natural number) cannot end with the digit zero.

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Answer 2

when n=1,2,3,4
than 4n will be 4×1=4
4×2=8
4×3=12
4×4=16
Hence 4n can't end with 0 or 5