Question

show that (4ab+3cd)^2-(4ab-3cd)^2_48 =abcd​

Answer 1

Step-by-step explanation:

Use this formula :

a^2 - b^2 = (a+b)(a-b)

Then ,

(4ab+3cd)^2-(4ab-3cd)^

= 48abcd + 36(cd)^2