Question

Show that :
(4ab + 3cd)2 – (4ab – 3cd)2
-= abcd
48​

Answer 1

Answer:

( 4ab + 3cd )2 - ( 4ab - 3cd )2 = abcd.

ab+cd ( 7 × 2 ) - ab-cd ( 1 × 2 ) = abcd.

abcd - abcd ( 14 × 2 ) = abcd.

abcd will get cancelled,

28 = abcd .

I think answer is this .

sorry for wrong answer.

but Iknow this much only.

pls follow me guy's

Answer 2

Answer:

Step-by-step explanation: