Question

show that 4n can't end with digit 2 for any natural number n.​

Answer 1

Step-by-step explanation:

If any number ends with 0 then it must be divisible by 5

Hence its prime factorization must contain 5

But we know 4=2×2

So, there is no natural number n for which 4

n

can end with 0.

Answer 2

Answer:

Hence, there is no natural number 'n' for which 4n. ends with the digit zero.

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