Virat Kohli smashes 96 runs against Australia in 20 balls. If he only scored in boundaries(fours and
sixes) only, then find the maximum percent of runs he scored by hitting fours(it is known that there is
no dot ball in his inning).
Answers
Answered by
1
Let number of balls with fours be x and number of balls with sixes be y
x+y=20, x=20-y
4x+6y=96
4(20-y)+6y=96
80-4y+6y=96
2y=16
y=8, x=12
Runs with fours= 48
Runs with sixes= 48
50% runs with fours and 50% with sixes
x+y=20, x=20-y
4x+6y=96
4(20-y)+6y=96
80-4y+6y=96
2y=16
y=8, x=12
Runs with fours= 48
Runs with sixes= 48
50% runs with fours and 50% with sixes
Answered by
0
Percentage of runs scored by fours = 50%
Percentage of runs scored by sixes = 50%
Let the number of fours = x
Number of sixes = y
we know that x + y = 20
and
4x + 6y = 96
Solving the above 2 equations, we get
x = 12 and y = 8
Runs scored with 12 fours = 12 * 4 = 48
Runs scored with 8 sixes = 8 * 6 = 48
The percentage of fours = 48/96 (100) %
= 50%
The percentage of sixes = 48/96 (100) %
= 50%
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