Math, asked by jaskeeratsingh8811, 6 months ago

Show that 4x^3-3x^2+2x+9 is a multiple of (x+1)

Answers

Answered by Anonymous
5

Answer:

x + 1

x = -1

_______

4x^3 - 3x^2 + 2x + 9

4 × ( -1 )^3 - 3 × ( -1 )^2 + 2 × ( -1 ) + 9

4 × ( -1 ) - 3 × 1 + 2 × ( -1 ) + 9

-4 - 3 -2 + 9

-9 + 9

0

______________

Hence , 4x^3 - 3x^2 + 2x + 9 is a multiple of ( x + 1 ) .

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