show that (4x-5)²+80x=(4x+5)
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Answer: 4x + 5)2 – 80x
= [(4x)2 + 2(4x) (5) + (5)2] – 80x (Using identity II)
= (16x2 + 40x + 25) – 80x
= 16x2 + 40x – 80x + 25
= 16x2 – 40x + 25
= (4x)2 – 2(4x) (5) + (5)2
= (4x – 5)2 (Using identity II)
= RHS
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