Question

Show that : (5x-4y)^2 + 80xy = (5x + 4y) ^2​

Answer 1

Step-by-step explanation:

$[(5x)^{2} -2(5x)(4y)+(4y)^{2} +80xy=(5x+4y)^{2} \\25x^{2} -40xy+16y^{2} +80xy=(5x+4y)^{2} \\25x^{2} -40xy+80xy+16y^{2} =(5x+4y)^{2} \\25x^{2} +40xy+16y^{2} =(5x+4y)^{2} \\(5x)^{2} +2(5x)(4y)+(4y)^{2} =(5x+4y)^{2} \\(5x+4y)^{2} =(5x+4y)^{2}$

Hence Proven

Hope this helps you