Show that 6n can not end with the digit 0 for any natural number n.
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This is not possible because 6n=(2×3)n, so the primes in the factorisation of 6n are 2and3.so the uniqueness of the fundamental theorem of arithmatic guarantees that there are no other primes in factorisation of 6n.so, there is no natural no. n for which 6n ends with the digit 0. Thanks
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