show that 7-√5 is irrational.given that √5 is irrational
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Given that ✓5 is irrational
if not so let 7-√5 be rational i.e =p/q where p and q are Co primes
by squaring on both sides we get
49-14√5+25=p^2/q^2
64-14√5=p^2/q^2
(p^2/q^2)-64/14 =√5
LHS is rational and RHS is irrational
since irrational is not equal to rational .therefore the give number is irrational
if not so let 7-√5 be rational i.e =p/q where p and q are Co primes
by squaring on both sides we get
49-14√5+25=p^2/q^2
64-14√5=p^2/q^2
(p^2/q^2)-64/14 =√5
LHS is rational and RHS is irrational
since irrational is not equal to rational .therefore the give number is irrational
sraddhavaranasi22:
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1
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