show that √7 is irrational
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Step-by-step explanation:
let us assume that √7 as irrational
so ,
√7 = a/b
b√7 = a
squaring on both sides , we get
7b² = a² -------------------------------------------------------- ( 1 )
if 7 divides a² then it also divides a
so ,
a = 7c
squaring on both sides , we get
a² = 49c²---------------------------------------------------------( 2 )
substitute equation( 1 )in equation (2 )
we get
7b² = 49 c²
b² = 7 c²
here a b and c have 7 as common factor
so 7 is rational number
but ,
√7 is irrational
this contradiction has arisen due to our incorrect assumption
this contradicts the fact that ,
√7 is a irrational number
hope it helps u
meghasg2004:
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