show that 7 root 5 is irrational number
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Answered by
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let us assume that 7√5 is rational
⇒7√5=p/q
⇒√5=p/7q
irrational=rational
which is a contradiction
∴our assumption is wrong
7√5 is irrational
⇒7√5=p/q
⇒√5=p/7q
irrational=rational
which is a contradiction
∴our assumption is wrong
7√5 is irrational
Answered by
1
okay,once again let us assume that 7√5 is rational.
so 7√5 = a/b (b≠0) ,where a and b are co-primes.
⇒ √5 = a/7b
here a, b and 7 are integers so it is rational.
therefore. √5 is also rational.
but this contradicts the fact that √5 is irrational.this contradiction has arrived due to our wrong assumption of 7√5 as rational.
hence, 7√5 is irrational.
so 7√5 = a/b (b≠0) ,where a and b are co-primes.
⇒ √5 = a/7b
here a, b and 7 are integers so it is rational.
therefore. √5 is also rational.
but this contradicts the fact that √5 is irrational.this contradiction has arrived due to our wrong assumption of 7√5 as rational.
hence, 7√5 is irrational.
Dakshansh:
please mark as the brainliest ^-^
thank u very much : )
actually i have learnt like that and it is the simpliest way
k fine thanks
u r from which school?
(if u r asking me) i study in kv
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