Show that 9 n cannot end in 2 for any positive integer n.
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Let, p(n) denotes the statement that 9ⁿ can not end with 2 for any positive integer n.
For n=1, p(1): 9¹=9, not ended with 2.
Let us assume that p(n) is true for n=k i.e., can not ended with 2.
For n=k+1, p(k+1):
=9^k.9
which can not be ended with 2 also since is not ended with 2.
Now p(1) is true and p(k+1) is true if p(k) is true. Then by the principle of mathematical induction 9ⁿ can not be ended with 2 for any positive integer n.
For n=1, p(1): 9¹=9, not ended with 2.
Let us assume that p(n) is true for n=k i.e., can not ended with 2.
For n=k+1, p(k+1):
=9^k.9
which can not be ended with 2 also since is not ended with 2.
Now p(1) is true and p(k+1) is true if p(k) is true. Then by the principle of mathematical induction 9ⁿ can not be ended with 2 for any positive integer n.
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hehe....
here is ur solution☺☺
here is ur solution☺☺
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sivaprasath:
if n = 8, then,. 9(8) = 72,.ends in 2 right?
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