show that 9^n cannot end with digit o for any natural number n
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Step-by-step explanation:
9n can never end with the digit 0 for any natural number n because for a number to end with zero it should be divisible by 10 and therefore its factors should be 5 and 2. But as 9 has only 3 as its factor, increasing its power will not make 5 as its factor. Thus it can never end with 0.
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heyy army!!!!
9 can never end with the digit 0 for any natural number n because for a number to end with zero it should be divisible 10 and therefore its factor should be 2 and 5 but as 9 has only three as its factor increasing its factor will not make 5 as its factor
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