Show that A(0,0), B(-5,5) are the vertices of right angled isosceles triangle.
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Let the vertices of the right isosceles triangle be A(0,0),B(5,5),C(-5,5)
AB=25+25=50
BC=(5+5)2+(5−5)2=100=10
AC=(−5−0)2+(5−0)2=50
∴AB=AC=50
∴ △ABC is an isosceles right angled
Also, AB2+AC2=BC2
⇒50+50=100
△ABC is an isosceles right-angled triangle.
Hope it helps you.
Answered by
0
Answer:
your answer is are the vetices
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