Math, asked by nallarithvika, 5 months ago

Show that A(0,0), B(-5,5) are the vertices of right angled isosceles triangle. ​

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Answered by chamolijagat9
3

Answer:

Let the vertices of the right isosceles triangle be A(0,0),B(5,5),C(-5,5)

AB=25+25=50

BC=(5+5)2+(5−5)2=100=10

AC=(−5−0)2+(5−0)2=50

∴AB=AC=50

∴ △ABC is an isosceles right angled

Also, AB2+AC2=BC2

⇒50+50=100

△ABC is an isosceles right-angled triangle.

Hope it helps you.

Answered by lnivetha45
0

Answer:

your answer is are the vetices

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