show that A[1 2 2
2 1 2
2 2 1] satisfy the equation
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1 2 2 A=2 1 2 2 2 1 Therefore, A? = A-A 1 2 2 [1 2 27 2 1 2 x 2 1 2 2 2 1 |2 2 1 [1+4+4 2+2+4 2+4 +21 9 8 8 = |2+2+4 4+1+4 4+2+2 =|8 9 8 [2+4+2 4 +2+2 4+4 +1 8 8 So, A2 – 4A – 51 9 8 8 [1 2 2 [1 0 0 -4 2 1 2 - 50 1 0 0 8 9 8. %3D 8 8 9 2 2 1 1 [9 8 8 [4 8 8] [5 0 0] 8. 9 8 8 4 8-50 5 0 8 9 8 4| 05 9-4-5 8-8-0 8-8-0 To o o 8-8-0 9-4-5 8-8-0 0 0 0 8-8-0 8-8-0 9-4-5 0 0 co Co 4,
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