show that (a+b)³= a³+ b³+ 3ab(a+b)
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Answered by
3
Step-by-step explanation:
(a+b)³=(a+b)(a²+2ab+b²)
(a+b)³=(a³+b³+3a²b+3b²a)
(a+b)³=a³+b³+3ab(a+b)
Answered by
0
(a+b)³=(a+b)²x(a+b)
=a²+2ab+b²(a+b)
=a³+a²b+2a²b+2ab²+ab²+b³
=a³+b³+3a²b+3ab²
=a³+b³+3ab(a+b)
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