Question

Show that;

(a-b) (a+b)+(b-c) (b+c)+(c-a) (c+a)=0​

Answer 1

Answer:

0=0

Step-by-steps explanation:

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Answer 2

Answer:

$the \: Answer \: of \: (a-b) (a+b)+(b-c) (b+c)+(c-a) (c+a) \: is \: 0 \:$