Question

SHOW THAT (a-b)squre, (a squre +b squre) and (a +b)squre ARE IN AP.

Answer 1

Answer:nope

Step-by-step explanation:your question is wrong please be correct it

Answer 2

Answer:

We need to show that the difference between the 2nd and 1st terms is the same as the difference between the 3rd and 2nd terms.

   Difference between 2nd and 1st terms

= ( a² + b² ) - ( a - b )²

= ( a² + b² ) - ( a² + b² - 2ab )

= a² + b² - a² - b² + 2ab

= 2ab

Difference between 3rd and 2nd terms

= ( a + b )² - ( a² + b² )

= ( a² + b² + 2ab ) - ( a² + b² )

= a² + b² + 2ab - a² - b²

= 2ab

As the differences are the same, the three terms are in arithmetic progression.

Hope this helps!