Show that (A-B) union (B-A) = (A union B)-(A intersection B)
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Step-by-step explanation:
SUPPOSE :-
Set A = {1,2,3,4}
Set B = { 3,4,5,6}
(A-B) ∪ (B-A) = (A∪B) - (A∩B)
(A-B) = {1,2} (A∪B) = {1,2,3,4,5,6}
(B-A) = {5,6} (A∩B) = {3,4}
(A-B)∪(B-A) = {1,2,5,6} = (A∪B) - (A∩B) = {1,2,5,6}
piyushkumar2526:
you have to prove not verify
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