Show that a diagonal of a parallelogram divides it into two congruent triangles.
(Hint: Use SSS congruence criterion)
it should not copyed from google
only sss congruence criterion method should be used
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Answer:
let llgm abcd ac diagonal ,
then we have triangle abc and bcd
ab=cd(opp. side of llgm)
bc =ad(""". """)
angle abc=angle bcd(abllbc)
triangle abc
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