Question

Show that a diagonal of a parallelogram divides it into two congruent triangles.
(Hint: Use SSS congruence criterion)

it should not copyed from google

only sss congruence criterion method should be used​

free points​

Answer 1

Step-by-step explanation:

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Answer 2

in a parallelogram ABCD , let BD Be the diagonal ;

and the diagonal divides the parallelogram into 2 triangles BAD and DCB

in triangle BAD and DCB

BD = BD ( COMMON SIDE )

AB = CD ( OPPOSITE SIDES ARE EQUAL )

AD = BC ( OPPOSITE SIDES ARE EQUAL )

FROM THE ABOVE EQUATION ,

BAD ~= DCB