Question

show that a quadrilateral ABC AB+BC+CD+DA>AC+BC​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

ABCD is a quadrilateral and AC, and BD are the diagonals.Sum of the two sides of a triangle is greater than the third side.So, considering the triangle ABC, BCD, CAD and BAD, we getAB + BC > ACCD + AD > ACAB + AD > BDBC + CD > BDAdding all the above equations,2(AB + BC + CA + AD) > 2(AC + BD)⇒ 2(AB + BC + CA + AD) > 2(AC + BD)⇒ (AB + BC + CA + AD) > (AC + BD)HENCE, PROVED

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