Question

show that a³+b³+c³= 3abc if a+b+c= 0​

Answer 1

Answer:

we need to use algebraic identity

Step-by-step explanation:

a3+b3+c3=3abc

a3+b3+c3-3abc= (a+b+c)(a2+b2+c2-ab-bc-ca)

if

a+b+c=0

=0(a2+b2+c2-ab-bc-ca)

=a3+b3+c3-3abc=0

=a3+b3+c3=0+3abc

=a3+b3+c3=3abc

hence it is proved

hope it helps you

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