show that ABC is isosceles if A=70°and B=40°
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sum of all sides is 180
angle A + angle B + angle C = 180
70+ 40+ angle C = 180
110 +angle C = 180
angle C =180-110
angle C =70
we know that in isosceles triangles two sides are equal angle A = angle C = 70
hence proved
angle A + angle B + angle C = 180
70+ 40+ angle C = 180
110 +angle C = 180
angle C =180-110
angle C =70
we know that in isosceles triangles two sides are equal angle A = angle C = 70
hence proved
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