Show that all the line segment drawn on a line from a given point not on it the perpendicular line segment is the shortest
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mark brainliest
mark brainliest
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Given: A straight line l and a point p not lying on l. PM perpendicular l and N is any point on l other than M.
To prove: PM<PN
Proof: In /\ PMN
angle M =90°
=>angle N<90° [ °•° angle M =90°=>MPN+PNM=90°
=>P+N=90°=>N<90°]
=>N<M
=>PM<PN [side opposite. to greater angle is larger]
Hence, PM is the shortest of all segments from P and AB.
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