show that angles of equilateral are 60
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GIVEN:
Draw a triangle ABC
ABC is an equilateral triangle
therefore AB=BC=CA
TO PROVE:
angle ABC=angle BAC=angle BCA=60
PROOF:
Triangle ABC,
AB=BC
Angle BCA=Angle ABC (1 eqn) (By the rule angles opposite to equal sides are equal)
similarly we can prove,
Angle BCA=Angle BAC (2 eqn)
Angle ABC=Angle BAC (3 eqn)
From equations 1,2,3 we get
angle ABC=angle BAC= angle BCA
Angle ABC+angle BAC+ angle BCA=180 (Angle sum property of a triangle)
As all the angles are equal,
3 x angle ABC=180 (as angle ABC=angle BAC= angle BCA)
Angle ABC=60
Therefore, Angle ABC=Angle BAC= Angle BCA=60
Hence proved....
Hope it helpss frnd!!!
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