Question

show that any number among (n+2),n and (n+4) is divisible by 3
 

Answer 1

(n+2)+n+(n+4)/3=0
(n+2)+n+(n+4)=0
3n+6=0
3n=-6
n=-6/3
n=-2

Answer 2

(n+2)+n+(n+4)/3=0
(n+2)+n+(n+4)=0
3n+6=0
3n=-6
n=-6/3
n=-2