Show that any positive even integer is in the form 4q, 4q+2 where q is some integer
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Step-by-step explanation:
Let a be the positive integer.
And, b = 4 .
Then by Euclid's division lemma,
We can write a = 4q + r ,for some integer q and 0 ≤ r < 4 .
°•° Then, possible values of r is 0, 1, 2, 3 .
Taking r = 0 .
→ a = 4q .
Taking r = 1 .
→ a = 4q + 1 .
Taking r = 2
→ a = 4q + 2 .
Taking r = 3 .
→ a = 4q + 3 .
But a is an even positive integer, so a can't be 4q + 1 , or 4q + 3 [ As these are odd ] .
∴ a can be of the form 4q or 4q + 2 for some integer q .
Hence , it is solved
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