show that any positive even integer is of the form 2q and positive odd integer of the form 2q+1 where q is some integer.
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Answered by
15
hey!!
^_^
________
we Let a be any positive integer and b=2.
Then, by Euclid's division lemma there exist integers q and r such that:-
a = 2q + r , where 0 </= r < 2
▪now, 0 </= r <2
=> 0</= r</= 1
=> r=0 or, r=1 ( because r is an integer)
▪therefore a =2 q, then a is an even integer.
▪we know that an integer can either be even or odd. Therefore any odd integer is of the form 2q +1.
____________________________________
hope help u
^_^
________
we Let a be any positive integer and b=2.
Then, by Euclid's division lemma there exist integers q and r such that:-
a = 2q + r , where 0 </= r < 2
▪now, 0 </= r <2
=> 0</= r</= 1
=> r=0 or, r=1 ( because r is an integer)
▪therefore a =2 q, then a is an even integer.
▪we know that an integer can either be even or odd. Therefore any odd integer is of the form 2q +1.
____________________________________
hope help u
Answered by
2
let a be any positive integer
then
b=2
0≤r<b
0≤r<2
r=0,1
case 1.
r=0
a=bq+r
2q+0
2q
case 2.
r=1
a=bq+r
2q+1
from above it is proved.
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