Show that any positive integer is form of 4q+1or4q+3, where q is some integer
Answers
Answered by
0
Question should be:
- Show that any odd positive integer is form of 4q+1or4q+3, where q is some integer.
ANSWER:
- All odd positive integer is in the form of 4q+1 , 4q+3 for some positive integer q.
GIVEN:
- A positive integer q .
TO PROVE:
- Any odd positive integer is form of 4q+1or4q+3, where q is some integer.
SOLUTION:
Let n be any positive integer which is divided by 4 we get some quotient 'q' and remainder 'r'
=> n = 4q+r. .....(i)
Where r = 0, 1 ,2 ,3
Putting r = 0 in eq(i)
=> n = 4q (Which is even)
Putting r = 1
=> n = 4q+1. (Which is odd)
Putting r = 2
=> n = 2(2q+1) ..(which is even)
Putting r = 3
=> n = 4q+3 (which is odd)
Here any odd positive integer is in the form of 4q+1 , 4q+3 for some positive integer q.
Similar questions