show that any positive odd integer is either even or odd.
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the correct answer is odd
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Hey!!!!!
let a be any positive integer.
let b = 2
Then by Euclid's Division Lemma,
=> a = 2q + r where 0 <= r < b
Thus r = 0 or 1
Case 1 , r = 0
=> a = 2q (even)
Case 2 , r = 1
=> a = 2q + 1 (odd)
HENCE PROVED
let a be any positive integer.
let b = 2
Then by Euclid's Division Lemma,
=> a = 2q + r where 0 <= r < b
Thus r = 0 or 1
Case 1 , r = 0
=> a = 2q (even)
Case 2 , r = 1
=> a = 2q + 1 (odd)
HENCE PROVED
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