Question

show that at the critical temperature the depression of and release gas law from ideal gas law 62.5%​

Answer 1

Explanation :

In the cyclic process : △=0

△Q=△W

△W=WA→B+WB→C+WC→A

WB→C=0 (Volume remains constant)

WA→B=P(V2−V1) (Pressure remains constant)

=10(2−1)=10J

Therefore , 5=10+WC→A

WC→A=−5J