show that bromine gas with Lewis dot structure
Answers
Answered by
7
It is a neutral Bromine gas.It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured gas.
Attachments:
Answered by
4
First calculate the number of electrons required (ER) to give every body an octet.
That would be: ER 2*8= 16
Then calculate how many electrons you actually have. Look in the periodic table. Bromine is in column 17. Ten of that is the d block, so subtract 10. Gives 7, being the valence electrons of a bromine atom
So total valence electrons VE = 2*7 = 14 electrons
In Lewis theory everything is paired, so divide by two, giving TP= 14/2= 7 total electron pairs.
You need to reconcile the discrepancy between ER and VE by sharing electrons.
Clearly ER-VE = 16–14 = 2 electrons. Divide by 2, this gives SP=1 shared pair.
Lastly subtract TP -SP = 7–1 = 6 = LP th number of lone pairs.
Now draw a structure.

Drawing the dots is pretty tedious. This is why an electron pair is usually given as a line - as in Br-Br. The lone pairs are usually also shown that way. Notice that there are indeed six of them.
That would be: ER 2*8= 16
Then calculate how many electrons you actually have. Look in the periodic table. Bromine is in column 17. Ten of that is the d block, so subtract 10. Gives 7, being the valence electrons of a bromine atom
So total valence electrons VE = 2*7 = 14 electrons
In Lewis theory everything is paired, so divide by two, giving TP= 14/2= 7 total electron pairs.
You need to reconcile the discrepancy between ER and VE by sharing electrons.
Clearly ER-VE = 16–14 = 2 electrons. Divide by 2, this gives SP=1 shared pair.
Lastly subtract TP -SP = 7–1 = 6 = LP th number of lone pairs.
Now draw a structure.

Drawing the dots is pretty tedious. This is why an electron pair is usually given as a line - as in Br-Br. The lone pairs are usually also shown that way. Notice that there are indeed six of them.
Similar questions