Question

show that bromine gas with Lewis dot structure

Answer 1

It is a neutral Bromine gas.It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured gas.

Answer 2

First calculate the number of electrons required (ER) to give every body an octet.

That would be: ER 2*8= 16

Then calculate how many electrons you actually have. Look in the periodic table. Bromine is in column 17. Ten of that is the d block, so subtract 10. Gives 7, being the valence electrons of a bromine atom

So total valence electrons VE = 2*7 = 14 electrons

In Lewis theory everything is paired, so divide by two, giving TP= 14/2= 7 total electron pairs.

You need to reconcile the discrepancy between ER and VE by sharing electrons.

Clearly ER-VE = 16–14 = 2 electrons. Divide by 2, this gives SP=1 shared pair.

Lastly subtract TP -SP = 7–1 = 6 = LP th number of lone pairs.

Now draw a structure.



Drawing the dots is pretty tedious. This is why an electron pair is usually given as a line - as in Br-Br. The lone pairs are usually also shown that way. Notice that there are indeed six of them.