Question

show that cos(90+theta) sec(-theta) tan(180-theta) / sec(360-theta) sin(180+theta) cot(90-theta) = -1

Answer 1

Hope you got your answer

Answer 2

$\frac{cos(90+ \alpha ).sec(- \alpha ).tan(180- \alpha )}{sec(360- \alpha ).sin(180+ \alpha ).cot(90- \alpha )}$

$\frac{-sin \alpha .sec \alpha .-tan \alpha }{sec \alpha .-sin \alpha .tan \alpha }$

$\frac{-sin \alpha. sec \alpha .tan \alpha }{sin \alpha. sec \alpha .tan \alpha }$

-1