show that cos sq 30−sin sq 30=(1−tan sq 30)÷1+tan squad 30
Answers
Answered by
0
Step-by-step explanation:
LHS= cos^2 30 - sin^2 30
= (root3/2)^2 - (1/2)^2
= 3/4 - 1/4
= 2/4
= 1/2
Now,
RHS = (1 - tan^2 30) / (1 + tan^2 30)
= 1 - ( 1/ root3)^2 / sec^2 30
= 1 - 1/3 / (2/ root3)^2
= (2/3)/ (4/3)
=2/3 * 3/4
=1/2
Hence, LHS=RHS proved.
Similar questions