show that cos130cos40+sin130sin40=0
Answers
Answered by
6
cos130cos40+sin130sin40
=cos(130-40)
[bcoz. cosAcosB+sinAsinB=cos(A-B)
=cos90
=0 =rhs
......hope it helps u.......
=cos(130-40)
[bcoz. cosAcosB+sinAsinB=cos(A-B)
=cos90
=0 =rhs
......hope it helps u.......
Answered by
5
cos130cos40+sin130sin40
=cos(130-40) [ cosAcosB+sinAsinB=cos(A-B)]
=cos90
=0
=rhs
=cos(130-40) [ cosAcosB+sinAsinB=cos(A-B)]
=cos90
=0
=rhs
Similar questions