Question

. Show that cos4A-Sin4A=1-2Sin2A ​

Answer 1

Prove:

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2A

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left side

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)=(cos^2+sin^2)(1-sin^2-sin^2)

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)=(cos^2+sin^2)(1-sin^2-sin^2)=1(1-2sin^2)

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)=(cos^2+sin^2)(1-sin^2-sin^2)=1(1-2sin^2)=1-2sin^2

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)=(cos^2+sin^2)(1-sin^2-sin^2)=1(1-2sin^2)=1-2sin^2verified:

Prove:Cos^4A - Sin^4A = 1 - 2Sin^2AStarting with left sidecos^4-sin^4=(cos^2+sin^2)(cos^2-sin^2)=(cos^2+sin^2)(1-sin^2-sin^2)=1(1-2sin^2)=1-2sin^2verified:left side = right side

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