Question

show that (cosecA-sinA)(secA-cosA)(tanA+cotA)=1

Answer 1

Answer:

Step-by-step explanation:

(cosecA-sinA)(secA-cosA)(tanA+cotA)

(1/sinA - sinA) (1/cosA - cosA) (1/cotA

+cotA)

(1-sin^2 A/sinA) (1-cos^2 A/cos A) (1-cot^2 A/cotA)

(cos^2 A /sinA) (sin^2 A /cosA) (cosec^2 A/cotA)

(cos^2 A /sinA) (sin^2 A /cosA) (1/sin^2 A /cosA/sinA)

(cos^2 A /sinA) (sin^2 A /cosA) (1/sinA /cosA/1)

(cos^2 A /sinA) (sin^2 A /cosA) (1/sinA.cosA)

(cos^2 A /sinA) (sin^2 A /cosA) (1/sinA.cosA)

CosA. SinA. (1/sinA.cosA)

1=RHS

PROVED

HOPE IT HELPS YA

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