show that de parallelogram bc if ar (triangle bce),= ar (triangle bcd)
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Given D and E are point on sides AB and AC respectively of triangle ABC such that Area(ΔBCD) = Area(ΔBCE).
Given that Area(ΔBCD) = Area(ΔBCE).
Then the height of triangle BCD and Triangle BCE are the same because both triangles are the same
Then it possible that both triangle on the same base and between parallel line BC and DE
Therefore, they will lie between the same parallel lines.
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