show that diagonals of a parallelogram divide it into 4 triangles of equal area
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Diagonals if a parallelogram divide it into 4 triangles is equal area.

And also diagonals divide the parallelogram into 4 triangles such that
Pair of opposite triangle are congruent..
We know that diagonals of a parallelogram bisect each other.
When you consider ∆ABC , BO is median
So median divide the triangle into 2 equal triangles of equal area.
So all the 4 smaller triangles are equal in area.
When you see pair of opposite triangles
They are congruent so the called it as 4 congruent triangles.
hope it helps
If I deserve mark it as Brainliest

And also diagonals divide the parallelogram into 4 triangles such that
Pair of opposite triangle are congruent..
We know that diagonals of a parallelogram bisect each other.
When you consider ∆ABC , BO is median
So median divide the triangle into 2 equal triangles of equal area.
So all the 4 smaller triangles are equal in area.
When you see pair of opposite triangles
They are congruent so the called it as 4 congruent triangles.
hope it helps
If I deserve mark it as Brainliest
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