Question

Show that diagonals of a rhombus intersects at right angle​

Answer 1

${\huge{\mathfrak{Answer:-}}}$

$<b>$Given that ABCD is a rhombus

then,

AB = BC = CD = AD.

To prove that diagonals AC and BD bisect each other.

Proof :

Given AB = CD.

In ΔAOB and ΔAOD

AO = AO (Common )

AB = AD (Given )

∠AOB + ∠AOD = 180° ( linear pair )

But ∠AOB = ∠AOD ( Vertically opposite angles)

∠AOB + ∠AOB = 180°

2∠AOB = 180° / 2

∠AOB = 90°

∴The diagonals AC and BD bisect each other

Answer 2

Hey mate your answer is here

In any rhombus the diagonal (lines linking opposite corners) bisect each other at right angle (90 degree) That is each diagonal cuts the other into two equal parts and the angle where they cross is always 90 degree

I hope its help you mate