Question

Show that electric field near a charged conductor is σ/εo where σ is the surface charge density.

Answer 1

Explanation:

HERE IS YOUR ANSWER MATE

Show that the electric field at the surface of a charged conductor is given by →E=σε0ˆn , where σ is the surface charge density and ˆn is a unit vector normal to the surface in the outward direction . Solution : Electric field at a point on the surface of charged conductor , E=14πε0QR2 .