Show that every even positive integer is in the form of 2 cube for some into integer cube
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let 'a' be any positive integer and b=2
By euclid's division algorithm
a=bq+r 0≤r<b
a=2q+r 0≤r<2
(i.e) r =0,1
r=0 , a=2q+0=> a=2q
r=1, a=2q+1
if a is the form of 2m then 'a' is an even integer and positive odd integer is of the form 2m+1
thank u for giving me this oppournity i hope this helps you
reference : ncert maths text book example 2
By euclid's division algorithm
a=bq+r 0≤r<b
a=2q+r 0≤r<2
(i.e) r =0,1
r=0 , a=2q+0=> a=2q
r=1, a=2q+1
if a is the form of 2m then 'a' is an even integer and positive odd integer is of the form 2m+1
thank u for giving me this oppournity i hope this helps you
reference : ncert maths text book example 2
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