show that every line segment has only one mid point
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Given:- In ∆ ABCD &E are mid- point of∆ABC
To prove:- 1] DE||BC
2] DE=1/2 BC
Construction:- through C draw a line|| to AB Extend. DE to point F. join CF
Proof:- In ∆ ADE & ∆ CEF
|_ADE=|_CFE( alternate angle)
|_AED=|_CEF (vertically opposite angles)
AE=EC(given)
∆ADE=~∆CEF
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