show that every positive even integer is of the form2q and that every poaative odd integer is of the form 2q+1 where q is some integer
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Answered by
6
let a be a positive integer
when it is divided by 2
then by euclid's division Lemma
we have a=2q+r
where 0≤r<2
so r=0,1
therefore a either equal to 2q or 2q+1
so 2q is divided by 2 and is even where as in case of odd it is opposite.
when it is divided by 2
then by euclid's division Lemma
we have a=2q+r
where 0≤r<2
so r=0,1
therefore a either equal to 2q or 2q+1
so 2q is divided by 2 and is even where as in case of odd it is opposite.
Anonymous:
welcome all
Answered by
3
Heya user !!!
Here's the answer you are looking for
Let us assume the number is say, x
By Euclid's lemma, x can be represented as
x = 2a + r ( where a is any integer and 0≤ r < 2)
So, the value of r can be either 0 or 1.
CASE 1
When r = 0
x = 2a
Since x is a multiple of 2, it is even. And hence every even positive number can be represented as 2q ( where q is any integer)
CASE 2
when r = 1
x = 2x + 1
x is not divisible by 2, so it is odd. And hence every odd number can be represented as 2q + 1 (where q is any integer)
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let us assume the number is say, x
By Euclid's lemma, x can be represented as
x = 2a + r ( where a is any integer and 0≤ r < 2)
So, the value of r can be either 0 or 1.
CASE 1
When r = 0
x = 2a
Since x is a multiple of 2, it is even. And hence every even positive number can be represented as 2q ( where q is any integer)
CASE 2
when r = 1
x = 2x + 1
x is not divisible by 2, so it is odd. And hence every odd number can be represented as 2q + 1 (where q is any integer)
★★ HOPE THAT HELPS ☺️ ★★
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