Show that exactly one of that umbers n, n+2 or n+4 is divisible by 3
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for n=4. n+2 =6 which is divisible by 3.
n+(n+2)+(n+4)=3n+6 =3 (n+1).
Hence, one of these is divisible by three .
n+(n+2)+(n+4)=3n+6 =3 (n+1).
Hence, one of these is divisible by three .
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ANSWER
Case I:
If n=3q
n+4=3q+4
n+2=3q+2
here n is only divisible by 3
Case II:
If n=3q+1
n+4=3q+5
n+2=3q+3=3(q+1)
Here only n+2 is divisible by 3
Case III:
If n=3q+2
n+2=3q+4
n+4=3q+2+4 =3q+6
Here only n+4 is divisible by 3
Hence, only one of the numbers n,n+2,n+4 is divisible by 3.
Hope it helps
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