Question

show that f=mv2/r is homogeneous

Answer 1

Answer:

We know Force F=mass×

acceleration---1

And given force F =mv^2/r---2

Equating 1 and 2 dimensionaly we get, ma=mv^2/r

MLT^-2=ML^2T^-2L^-1

MLT^-2=MLT^-2.

Explanation:

@.•♫•♬•Dare•♬•♫•.

Answer 2

Answer:

Given

GivenF=mV²/r

GivenF=mV²/rDimensional Formula of Force= mx a

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L =M¹L²T⁻²/L

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L =M¹L²T⁻²/L =M¹L¹T⁻²------------(2)

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L =M¹L²T⁻²/L =M¹L¹T⁻²------------(2)By equation 1 and 2

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L =M¹L²T⁻²/L =M¹L¹T⁻²------------(2)By equation 1 and 2L.H.S =R.H.S

GivenF=mV²/rDimensional Formula of Force= mx a =mxv/t L.H.S=F =M¹L¹T⁻²---------(1)R.H.S=mv²/r =M¹(L¹T⁻¹)²/L =M¹L²T⁻²/L =M¹L¹T⁻²------------(2)By equation 1 and 2L.H.S =R.H.SSince the dimensions of F and mV²/r are equal... so equation is dimensionally correct.

Explanation:

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